难度3,出现频率3
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / \ 2 5 / \ \ 3 4 6The flattened tree should look like:
1 \ 2 \ 3 \ 4 \ 5 \ 6
思路: 用递归挺简单的--第一个一次通过bug free的代码,oh yeah!
void flatten(TreeNode *root) { if(root == NULL) return;
flatten(root->left);
flatten(root->right);
TreeNode *temp = root->right;
root->right = root->left;
root->left = NULL; TreeNode *cur = root;
while(cur->right != NULL){
cur = cur->right;
}
cur->right = temp; }
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