难度4,出现频率2
The gray code is a binary numeral system where two successive values differ in only one bit.
Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.
For example, given n = 2, return
[0,1,3,2]
. Its gray code sequence is:00 - 0 01 - 1 11 - 3 10 - 2Note:
For a given n, a gray code sequence is not uniquely defined.
For example,
[0,2,3,1]
is also a valid gray code sequence according to the above definition.For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.
vector<int> grayCode(int n) {
vector<int> res;
if(n == 0){ res.push_back(0); return res;}
vector<int> last = grayCode(n-1);
res.insert(res.end(), last.begin(), last.end());
vector<int> :: iterator it = last.end() - 1;
while( it != last.begin() - 1 ){
res.push_back((1<<(n-1)) + *it);
it--;
}
return res;
}
注:如果不用recursive function call,直接写是这个样子:
(copy from UniEagle)
vector<int> grayCode(int n) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int> ret; ret.push_back(0); if (n <= 0) return ret; int mostbit = 1; for(int i = 1; i <= n; ++i) { for(int k = ret.size() - 1; k >= 0; --k) { int v = ret[k]; ret.push_back(v | mostbit); } mostbit = mostbit << 1; } return ret; }
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